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Longest Common Subsequence
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| // recursive version , computes many subproblems again and again | |
| int lcsRecursive(string& s1, string& s2, int i, int j){ | |
| if(i >= s1.length() || j >= s2.length()) return 0; | |
| if(s1[i] == s2[j]) return 1 + lcsRecursive(s1, s2, i+1, j+1); | |
| else{ | |
| return max(lcsRecursive(s1, s2, i+1, j), lcsRecursive(s1, s2, i, j+1)); | |
| } | |
| } | |
| // saves results for previously computed subproblems thus reducing the recursion tree exponentially. | |
| int lcsBottomUp(string& s1, string& s2, int len1, int len2){ | |
| int results[len1+1][len2+1]; | |
| for(int i = 0; i <= len2; i++) results[0][i] = 0; | |
| for(int j = 0; j <= len1; j++) results[j][0] = 0; | |
| for(int i = 1; i <= len1; i++){ | |
| for(int j = 1; j <= len2; j++){ | |
| if(s1[i-1] == s2[j-1]){ | |
| results[i][j] = 1 + results[i-1][j-1]; | |
| }else{ | |
| results[i][j] = max(results[i-1][j], results[i][j-1]); | |
| } | |
| } | |
| } | |
| return results[len1][len2]; | |
| } |
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