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Python's example function `require` that imports file by path (like in PHP or JavaScript), with custom module's name and without creating bytecode.
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import sys | |
from pathlib import Path | |
import importlib | |
import runpy | |
def require(file, name=None): | |
if name is None: | |
name = Path(file).stem | |
anonymous = lambda cls: cls(name, str(Path(__file__).parent / file)) | |
@anonymous | |
class loader(importlib.machinery.SourceFileLoader): | |
"""This loader does't save bytecode""" | |
def set_data(self, *args, **kwargs): | |
raise NotImplementedError | |
spec = importlib.util.spec_from_loader(name, loader) | |
sys.modules[spec.name] = module = importlib.util.module_from_spec(spec) | |
loader.exec_module(module) | |
return module | |
a = require('foo.py') | |
assert a.Foo().bar == require('foo.py', 'b').bar() | |
print(a.__file__) | |
print(a.__name__) | |
print(a.Foo().__class__) | |
# Alternative way using runpy package: get file as a dict instead of a module | |
def execute(file, name=None): | |
if name is None: | |
name = Path(file).stem | |
return runpy.run_path(str(Path(__file__).parent / file), run_name=name) | |
b = execute('foo.py') | |
assert b['Foo'].x == execute('foo.py', 'c')['xyz'] | |
print(b['__file__']) | |
print(b['__name__']) | |
x = b['Foo']() | |
print(x.__class__) | |
# Can be easily turned into an object and used like a module | |
class NS: | |
def __init__(self, file, name=None): | |
self.__dict__.update(execute(file, name)) | |
c = NS('foo.py', 'bar') | |
# pylint: disable=no-member | |
print(c.__name__) | |
print(c.xyz) |
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class Foo: | |
x = 'xyz' | |
def __init__(self): | |
self.bar = 111 | |
def bar(): | |
return 111 | |
xyz = 'xyz' | |
print(f'--- {__file__} executed with name: {__name__} ---') |
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