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jQuery.hasClassRegEx() hasClass by using a Regex
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(function($) | |
{ | |
$.fn.hasClassRegEx = function(regex) | |
{ | |
var classes = $(this).attr('class'); | |
if(!classes || !regex){ return false; } | |
classes = classes.split(' '); | |
var len = classes.length; | |
for(var i=0; i<len; i++) | |
{ | |
if(classes[i].match(regex)){ return true; } | |
} | |
return false; | |
}; | |
})(jQuery); | |
/* | |
<span id="hasClassRegEx" class="Test Testing someTest aaTestaa"></span> | |
$("#hasClassRegEx").hasClassRegEx(); // false | |
$("#hasClassRegEx").hasClassRegEx(''); // false | |
$("#hasClassRegEx").hasClassRegEx('Test'); // true | |
$("#hasClassRegEx").hasClassRegEx(/ /); // false | |
$("#hasClassRegEx").hasClassRegEx(/Test/); // true | |
$("#hasClassRegEx").hasClassRegEx(/^Test/); // true | |
$("#hasClassRegEx").hasClassRegEx(/Test$/); // true | |
$("#hasClassRegEx").hasClassRegEx(/^Test$/); // true | |
$("#hasClassRegEx").hasClassRegEx(/test/); // false | |
$("#hasClassRegEx").hasClassRegEx(/test/i); // true | |
*/ |
@Euiyeon I see your comment only now... Sorry for the delay and thank you for the alert. It's updated now.
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Please correct the incorrect equation.
Line 12:
for(var i=0; i>len; i++)
// -->
i < len