conversion between iso8601 date format and unix epoch datetime

gistfile1.py

from datetime import datetime
import calendar

def epoch_to_iso8601(timestamp):
    """
    epoch_to_iso8601 - convert the unix epoch time into a iso8601 formatted date

    >>> epoch_to_iso8601(1341866722)
    '2012-07-09T22:45:22'
    """
    return datetime.fromtimestamp(timestamp).isoformat()

def iso8601_to_epoch(datestring):
    """
    iso8601_to_epoch - convert the iso8601 date into the unix epoch time

    >>> iso8601_to_epoch("2012-07-09T22:27:50.272517")
    1341872870
    """
    return calendar.timegm(datetime.strptime(datestring, "%Y-%m-%dT%H:%M:%S.%f").timetuple())

if __name__ == "__main__":
    import doctest
    doctest.testmod()

So much simpler:

If you want to get the seconds since epoch, you can use python-dateutil to convert it to a datetime object and then convert it so seconds using the strftime method. Like so:

>>> import dateutil.parser as dp
>>> t = '1984-06-02T19:05:00.000Z'
>>> parsed_t = dp.parse(t)
>>> t_in_seconds = parsed_t.strftime('%s')
>>> t_in_seconds
'455047500'

from: http://stackoverflow.com/a/27246418/1224827

That's not right. strftime will use local time zone, so you're epoch answer does not match 1984-06-02T19:05:00.000Z

Using actual UTC functions:

calendar.timegm(dateutil.parser.parse('2017-03-08T14:55:24Z').timetuple())

You can use that:

>>> from dateutil.parser import parse
>>> parse('2017-03-08T14:55:24Z').timestamp()
1488984924.0

You can use that:

>>> from dateutil.parser import parse
>>> parse('2017-03-08T14:55:24Z').timestamp()
1488984924.0

Works well for me. Thanks.