Created
December 15, 2012 03:54
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你懂得……扯上IO就会很麻烦…………
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import Data.Array | |
import Data.Array.IO | |
import Data.Ix | |
lcs :: String -> String -> Int | |
lcs s t = a!(n,m) | |
where a = array ((0,0),(n,m)) [((x,y), f x y)|x<-[0..n],y<-[0..m]] | |
n = length s | |
m = length t | |
s'= array (0,n-1) $ zip [0..n-1] s | |
t'= array (0,m-1) $ zip [0..m-1] t | |
f :: Int->Int->Int | |
f i j | |
| min i j == 0 = 0 | |
| s'!(i-1)==t'!(j-1) = a!(i-1,j-1) +1 | |
| otherwise = max (a!(i-1,j)) (a!(i,j-1)) | |
type TheArraysYouKnow = ( | |
IOUArray (Int,Int) Int , -- main table | |
IOUArray Int Char, -- s | |
IOUArray Int Char -- t | |
) | |
lcsIO :: String -> String -> IO Int | |
lcsIO s t = do | |
let n = length s | |
m = length t | |
theArrayYouKnow <- newListArray ((0,0),(n,m)) (repeat 0) | |
theSArray <- newListArray (0,n-1) s | |
theTArray <- newListArray (0,m-1) t | |
mapM_ (theFunctionYouKnow (theArrayYouKnow , theSArray ,theTArray ))$ range ((0,0),(n,m)) | |
readArray theArrayYouKnow (n,m) | |
where | |
theFunctionYouKnow ::TheArraysYouKnow -> (Int,Int) -> IO () | |
theFunctionYouKnow (a,s,t) (i,j) | |
| min i j == 0 = writeArray a (i,j) 0 | |
| otherwise = do | |
sChar <- readArray s (i-1) | |
tChar <- readArray t (j-1) | |
if (sChar == tChar ) then do | |
lookback <- readArray a (i-1,j-1) | |
writeArray a (i,j) (lookback + 1) | |
else do | |
left <- readArray a (i-1,j) | |
right <- readArray a (i,j-1) | |
writeArray a (i,j) (max left right) |
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