JS: Get only a number twice

index.js

var integers = []

// Generate 10 integers
for (var i = 0; i < 10; i++) {
  var number

  do {
    // Keep generating a random number if it's already in the array twice.
    number = random(5)
  } while(getCountInList(number) >= 2)

  integers.push(number)
}

console.log(integers)

// Find how many of a given number is in the list
// Example: Find how many number 1 is in the list.
function getCountInList(number) {
  return integers.filter(integer => integer === number).length
}

// Get random number from 0 to X.
function random(max) {
  return Math.floor(Math.random() * Math.floor(max));
}