Created
May 17, 2023 16:44
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Java code to (mimic) extending the array (v1)
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import java.util.ArrayList; | |
import java.util.List; | |
public class Main { | |
public static void main(String[] args) { | |
// Q. | |
// Take 10 integer inputs from user and store them in | |
// an array. Now, copy all the elements in | |
// an another array but in reverse order. | |
// 3 rooms / 3 blocks | |
ArrayList<Integer> fruits = new ArrayList<>(); | |
fruits.add(100); | |
fruits.add(200); | |
fruits.add(300); | |
// The array is full / overflow !!!! // | |
// ---------------------------------- // | |
// ------ NEW ERA ----------- // | |
// fruits -> 3 -> 4 = 400 | |
extend(fruits); | |
} | |
public static ArrayList extend(ArrayList previousArray) { | |
// 1. We need allocate a brand new array with +1 capacity | |
// 2. We need to copy the contents of previous array inside the new array | |
// 3. In the last, we just need to return the brand new array | |
// 1. | |
// Here we created a brand new array with +1 capacity | |
// int[] prev = new int[3] (old) | |
// int[] new = new int[previousArray.length + 1] (new) | |
ArrayList<Integer> newArray = new ArrayList<>(); | |
// 2. | |
for (int i = 0; i < 3; i++) { | |
newArray.add((Integer) previousArray.get(i)); | |
} | |
// 3. | |
return newArray; | |
} | |
} |
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