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September 18, 2025 07:35
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Serialize-Deserialize a BT / BST
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| # Leetcode : 449 | |
| # Definition for a binary tree node. | |
| # class TreeNode: | |
| # def __init__(self, x): | |
| # self.val = x | |
| # self.left = None | |
| # self.right = None | |
| class Codec: | |
| def serialize(self, root: Optional[TreeNode]) -> str: | |
| """ | |
| Encodes a tree to a single string. | |
| """ | |
| data = [] | |
| def preorder(node: Optional[TreeNode]): | |
| nonlocal data | |
| # Node -> Left -> Right | |
| data.append(f"{node.val}" if node else "X") | |
| if node: | |
| preorder(node.left) | |
| preorder(node.right) | |
| return | |
| preorder(root) | |
| return ":".join(data) | |
| def deserialize(self, data: str) -> Optional[TreeNode]: | |
| """ | |
| Decodes your encoded data to tree. | |
| """ | |
| data = data.split(":") | |
| n = len(data) | |
| i = 0 | |
| def preorder(): | |
| nonlocal i | |
| if i < n: | |
| v = data[i] | |
| i = i + 1 | |
| if "X" != v: | |
| node = TreeNode(v) | |
| node.left = preorder() | |
| node.right = preorder() | |
| return node | |
| return None | |
| return preorder() | |
| # Your Codec object will be instantiated and called as such: | |
| # Your Codec object will be instantiated and called as such: | |
| # ser = Codec() | |
| # deser = Codec() | |
| # tree = ser.serialize(root) | |
| # ans = deser.deserialize(tree) | |
| # return ans |
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