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#!/usr/bin/python | |
""" | |
Simple tool to extract local users and passwords from most Huawei routers/firewalls config files. | |
Will extract plain-text passwords and crypted credentials. Huawei config files use DES encryption with | |
a known key. Using this information, the script will decrypt credentials found in the config file. | |
Author: Etienne Stalmans ([email protected]) | |
Version: 1.0 (12/01/2014) | |
""" | |
from Crypto.Cipher import DES | |
import sys | |
import binascii | |
def decode_char(c): | |
if c == 'a': | |
r = '?' | |
else: | |
r = c | |
return ord(r) - ord('!') | |
def ascii_to_binary(s): | |
assert len(s) == 24 | |
out = [0]*18 | |
i = 0 | |
j = 0 | |
for i in range(0, len(s), 4): | |
y = decode_char(s[i + 0]) | |
y = (y << 6) & 0xffffff | |
k = decode_char(s[i + 1]) | |
y = (y | k) & 0xffffff | |
y = (y << 6) & 0xffffff | |
k = decode_char(s[i + 2]) | |
y = (y | k) & 0xffffff | |
y = (y << 6) & 0xffffff | |
k = decode_char(s[i + 3]) | |
y = (y | k) & 0xffffff | |
out[j+2] = chr(y & 0xff) | |
out[j+1] = chr((y>>8) & 0xff) | |
out[j+0] = chr((y>>16) & 0xff) | |
j += 3 | |
return "".join(out) | |
def decrypt_password(p): | |
r = ascii_to_binary(p) | |
r = r[:16] | |
d = DES.new("\x01\x02\x03\x04\x05\x06\x07\x08", DES.MODE_ECB) | |
r = d.decrypt(r) | |
return r.rstrip("\x00") | |
f_in = open(sys.argv[1],'r') | |
print "[*] Huawei Password Decryptor" | |
for line in f_in: | |
if ('local-user' not in line) or ('password' not in line): | |
continue | |
inp = line.split() | |
print "[*]-----------------------" | |
print "\t[+] User: %s"%inp[1] | |
print "\t[+] Password type: %s"%inp[3] | |
if inp[3] == "cipher": | |
print "\t[+] Cipher: %s"%inp[4] | |
print "\t[+] Password: %s"%decrypt_password(inp[4]) | |
else: | |
print "\t[+] Password: %s"%(inp[4]) |
Hi SwimmingTiger or anyone in this forum,
Can someone kindly help me to decrpyt this : Unable to render expression.$2RW!aHei\s+Ng_XGkJJ1EJE><2[4w7Hm)0>ZnNHVMkh'|~E=r4_-G5ME-5bm4)60{(<<:|1:p"N.TAi+Y7"{I<MQeM@@:Da.4:8wK$
My goal is to setup a bridge connection as the default ONT from ISP is not good enough for my usage. Currently setting up a bridge is not possible right now since myISP refuse to give the PPoE password.
I can do it for you for free but i have to visiting you i leve in qatar بني هاجر
Hello @qatar2030 Please share your contact details i'm intersted or whatsapp me on +201123547811
Hello,
Can someone decrypt this
%$%$Tr_3Df|s6VDf6|1)A&{("KB9%$%$
%$%$N\VpOW$0S9]y*Hk\d#/>bYP%$%$6-%$%$
%$%$7k"P64W3S#_ZoB3nb3'.vKB9%$%$
%$%$oR:@125YZLqM,41mdg"DE
%$%$TyIDAD_l6Hk[vx<Z5fQPYpg^%$%$
%$%$HIWgCp$,qHg).|3(&Eb<{6-%$%$kzE@*4j70WhWNE%$%$
%$%$HP.RQA%Ba
from a Eudemon1000E-X5
Hello, Can someone decrypt this
Hi there! Any reason you're not decrypting it yourself?
Hi guys has anyone teste Encryption and Decryption on Huawei AX2 wifi6 routers? it seems the user is allways the same: admin.. just password on input menu login screen.. i have managed to analyze with F12 network traffic.. and it has 2 requests.. user_login_nonce, and user_login_proof which returns a RSAE : 010001 and RSA_N public modulus and RSA signature and Server signature keys , together with CSRF tokens for security protection.. on the user_login_nonce the password seems to be encripted.. and we can only see a SALT key info
hello, can anyone decript this?
local-user root password irreversible-cipher g-1CeT32Y$..R"-F[fW<;W15,m-yn>.Y.-J>{wC@@
Q|,!+Q&G$
can anyone decrypt that:
What is SU button function on GUI I ever try $1 and $2 only
I don't know.
Where i can find this GUI ?
sorry for inconviniace,
What is SU button function on GUI I ever try $1 and $2 only
I don't know.
Where i can find this GUI ?
Thanks
@Boboaung-Myanmar - Try this 18855117
$2M^7i5]ps.KDN0XI>kLtUo{cZ~\ZMZ2R.*.POxM|2t-Z'6"e{P~e6WM9D^[l)DtF8(_]48(b$v9WjPQ,&+0fO>c'Nb/_b||6$;,rR$
Can you helpme ser
sorry for inconviniace,
What is SU button function on GUI I ever try $1 and $2 only
I don't know.
Where i can find this GUI ?
Thanks
$2M^7i5]ps.KDN0XI>kLtUo{cZ~\ZMZ2R.*.POxM|2t-Z'6"e{P~e6WM9D^[l)DtF8(_]48(b$v9WjPQ,&+0fO>c'Nb/_b||6$;,rR$
Can you helpme ser
Hello!
It it possible to decrypt this one?
$1c$nIyL.#{5F2$TzF'@"gEaH_mJb*Vd>fBD"px&M1'i1aOXF:ptG:E$
Thank you in advance!
for dg 8245
i need Administrator user and password
i search through notpade and this what i get
UserName="vodadsl" Password="41a69149e63df1ce83234fc39a70caeab11eed3d390629ca7cffc2dcd327480b" UserLevel="0" Enable="1" ModifyPasswordFlag="0"
i need to decrypt the password
$2GACZYhI-vIoR>v/Cdi:7dkP=;9/(HKvZ2UK[5,]AA9ALE\Z%.S*&iVCn216/StW,(M%
'bpB{@[jdL!1:Be=`9P*Ky}2(&|=jsR$
pls
i tried the site, it doesnt give a good result:
https://andreluis034.github.io/huawei-utility-page/#cipher
$2#$A:@i5s+L7OAK/KQ.r9gfB`5v,-S%T=rz~&0[6I:Zt,<Rvhz):[v3(*"K@(OMJMf<*aA1z#1KIlO4LUwr,FX$5D||9s)E#|%0$
Result: bbf2073ca9c495606fe49628cffef83e0dfce8dc29270703b3c6709e14029911
I can do it for you for free but i have to visiting you i leve in qatar بني هاجر