Create tree structure from paths array

index.js

var paths = [
    ["Account"],
    ["Account", "Payment Methods"],
    ["Account", "Payment Methods", "Credit Card"],
    ["Account", "Payment Methods", "Paypal"],
    ["Account", "Emails"],
    ["Account", "Emails", "Main Email"],
    ["Account", "Emails", "Backup Email"],
    ["Account", "Devices"],
    ["Account", "Devices", "Google Pixel"],
    ["Account", "Devices", "iPad Mini"],
    ["Account", "Devices", "Laptop"]
];

var tree = arrangeIntoTree(paths);
console.log(JSON.stringify(tree, null, 4));

// Result
// [
//     {
//         "name": "Account",
//         "children": [
//             {
//                 "name": "Payment Methods",
//                 "children": [
//                     {
//                         "name": "Credit Card",
//                         "children": []
//                     },
//                     {
//                         "name": "Paypal",
//                         "children": []
//                     }
//                 ]
//             },
//             {
//                 "name": "Emails",
//                 "children": [
//                     {
//                         "name": "Main Email",
//                         "children": []
//                     },
//                     {
//                         "name": "Backup Email",
//                         "children": []
//                     }
//                 ]
//             },
//             {
//                 "name": "Devices",
//                 "children": [
//                     {
//                         "name": "Google Pixel",
//                         "children": []
//                     },
//                     {
//                         "name": "iPad Mini",
//                         "children": []
//                     },
//                     {
//                         "name": "Laptop",
//                         "children": []
//                     }
//                 ]
//             }
//         ]
//     }
// ]

function arrangeIntoTree(paths) {
    // Adapted from http://brandonclapp.com/arranging-an-array-of-flat-paths-into-a-json-tree-like-structure/
    var tree = [];

    for (var i = 0; i < paths.length; i++) {
        var path = paths[i];
        var currentLevel = tree;
        for (var j = 0; j < path.length; j++) {
            var part = path[j];

            var existingPath = findWhere(currentLevel, 'name', part);

            if (existingPath) {
                currentLevel = existingPath.children;
            } else {
                var newPart = {
                    name: part,
                    children: [],
                }

                currentLevel.push(newPart);
                currentLevel = newPart.children;
            }
        }
    }
    return tree;

    function findWhere(array, key, value) {
        // Adapted from https://stackoverflow.com/questions/32932994/findwhere-from-underscorejs-to-jquery
        t = 0; // t is used as a counter
        while (t < array.length && array[t][key] !== value) { t++; }; // find the index where the id is the as the aValue

        if (t < array.length) {
            return array[t]
        } else {
            return false;
        }
    }
}

Just what I needed 👍 Thanks!

Hey, it's pure gold - exactly what I was Looking for. I am using it to build tree structure based on array of URL's. Of course, firstly I've split every url into an array of paths. Then to achieve fullUrl of current path I had to change one thing, link so:
var newPart = { fullUrl: path .slice(0, j + 1) .join("/") .replace("http/", "http://") .replace("https/", "https://"), name: part, children: [], };

Just what I need Thanks

Thanks.

Thanks , it works for me .

Thanks a lot man saved my day

Thank u bro <3

still perfect work 👍

might be missing something but does line 90 need to be there? seems to be working without it?

@nickgrato

might be missing something but does line 90 need to be there? seems to be working without it?

Honestly ... I don't know ... it's been so many years since I wrote the code ^^

@nickgrato

might be missing something but does line 90 need to be there? seems to be working without it?

Honestly ... I don't know ... it's been so many years since I wrote the code ^^

haha yes 5 years, very fair - this was helpful non the less thank you!

Thanks! I ended up writing a more modern typescript version of it.
Its input-output is a bit different as it works with data objects instead of plain paths.
This allows to have data attached / retained to every path node.

export interface TreeNode<TData=any> {
	name:string,
	children?:TreeNode[],
	data?:TData,
}

export function arrangeObjectsIntoTree<TData extends Record<string,any>>(objects:TData[], pathProperty:string):TreeNode<TData>[] {
	const tree = [];

	for (let i = 0; i < objects.length; i++) {
		const obj = objects[i];

		let path:string[];
		if(Array.isArray(obj[pathProperty])) path = obj[pathProperty] ;
		else if (typeof obj[pathProperty] === 'string') path = obj[pathProperty].split('/');
		else throw new Error('Could not parse path property')

		let currentParentNodeList:TreeNode<TData>[] = tree;

		for (let j = 0; j < path.length; j++) {
			const pathSegment = path[j];
			const isFinalSegment = j+1 === path.length;
			const existingNode = currentParentNodeList.find(node=>node.name === pathSegment)

			if (existingNode) {
				currentParentNodeList = existingNode.children;
			} else if(isFinalSegment) {
				currentParentNodeList.push({
					name: pathSegment,
					data: obj,
				});
			} else {
				currentParentNodeList.push({
					name: pathSegment,
					children: [],
				});
				currentParentNodeList = currentParentNodeList[currentParentNodeList.length-1].children;
			}
		}
	}
	return tree;
}

Usage example:

arrangeObjectsIntoTree([
  { foo:'bar', path:'my/tree/dir' },
  { foo:'bar', path:['my','other','dir'] },
], 'path'

Just like the original script, it will create a nested structure of objects containing name and children properties.
Additionally, each "entry" node will contain a data property which stores the original object.