Yep, it is the same hash as if we had the full value. Here is an example:
If we had all the data upfront:
> crc32c(new Buffer('data1data2data3'))
772160458If we have to calculate bit-by-bit:
> data1 = new Buffer('data1')
> data2 = new Buffer('data2')
> data3 = new Buffer('data3')
> sum = crc32c(data1) // first data chunk
2984452918
> sum = crc32c(data2, sum) // combine second data chunk with "sum"
4234036460
> sum = crc32c(data3, sum) // combine third data chunk with "sum"
772160458