Created
May 14, 2017 11:59
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@FunctionalInterface | |
public interface SimpleFunctionalInterface { | |
public int returnAnswerToUltimateQuestion(); | |
} | |
@Test | |
public void normalInterfaceOnlyOneAbstractMethod() { | |
int x = 1; | |
SimpleFunctionalInterface myInterfaceImpl = () -> { | |
// x = 2; // impossible | |
instanz = 3; // possible because member variables are copied when creating lambdas. (http://stackoverflow.com/questions/25055392/lambdas-local-variables-need-final-instance-variables-dont) | |
// TODO: Why is the class, in which the lambda is defined, copied? I thought that lambdas are "closed" definitions of functionality that can be passed around. | |
return 0; | |
}; | |
} |
Thanks a lot! Changed my workshop accordingly. Could you please have a look at this commit? It should contain everything important, but a review would be nice. :)
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I do not like the term
copied
and I don't like the answers on stackoverflow either ... might want to provide my own.If a lambda accesses a field, this is what happens (I'm making this stuff up as I go. I did not read the Java specification for this, nor did I look at the source code of javac:
The lambda gets translated into a class, including a constructor.
If the lambda accesses a field of the enclosing class a reference to the instance gets passed into the constructor of the lambda.
=> it can read and write fields
=> it can read the instance, i.e.
this
but it can't change wherethis
is pointing to. Read up aboutthis
in JS why this limitation is a good thing.If the lambda accesses a local variable (or parameter), that parameter gets passed in as another constructor argument.
=> it can read and write fields of that variable
=> it can read the variable, but it can't change where the pointer to the variable points to.