Read hexa data and covert to double in binary file

hextodouble.py

# python 3.x
from types import *
import struct
from struct import unpack
import numpy as np
import binascii
import functools
import sys


def hextodouble(value):
    bytes = list( map(ord,reversed(value)) )
    sign = (1,-1)[bytes[0]>>7]
    exp = ((0x7f&bytes[0])<<4) + (bytes[1]>>4) - 1023
    mantissa = functools.reduce(lambda x,y: (x<<8) + y, bytes[2:], bytes[1]&0xf)
    return sign*2**exp*(1+mantissa*2**-52) 

file = open('#1.wtf', 'rb')
file.seek(0x4EC)
rows = file.read(2)
file.close()
rows = int.from_bytes(rows,'little') 
print( rows )

file = open('#1.wtf', 'rb')
file.seek(0x4708)
double = 8
total = 8*(rows+2)
points = file.read( total )
file.close()

x = []
y = []

for r in range( rows+1 ):
    p= []
    for c in range( 8 ):
        i=8*r+c
        s = points[i]
        b = bytes([s]) # Convert byte to int
        p.append ( b )
        if c == 7 :
            if (c == 7) :
            if (r%2 == 0) :
                x.append( hextodouble ( p ) )
            else:
                y.append( hextodouble ( p ) )

print( x,y )