Promise all with timeout

promise-all-with-timeout.js

const timedPromise = () => {
  return new Promise((resolve, reject) => {
  
    console.log('promise1 started');
  
    setTimeout(() => {
    	resolve('promise1')
    }, 3000);
  });
}

const promise2 = Promise.resolve('promise2');

const allPromises = [];

[timedPromise(), promise2].forEach((p) => {
  allPromises.push(p);
});

Promise
  .all(allPromises)
  .then((results) => {
    console.log(results);
  });