Created
August 17, 2014 06:44
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Diamond-square Algorithm
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<!doctype html> | |
<html> | |
<head> | |
<title>Diamond-square</title> | |
</head> | |
<body> | |
<script> | |
// PRNG | |
function random(i) { | |
return (Math.sin(Math.sin(1e9*i)*1e6)+1)*0.5; | |
} | |
// Seemless clouds | |
// size is power of two | |
function diamondSquare(size, seed) { | |
var data = [ | |
[.5, .5], | |
[.5, .5] | |
]; | |
var canvas = document.createElement('canvas'); | |
canvas.width = canvas.height = size; | |
var ctx = canvas.getContext('2d'); | |
var imgData = ctx.createImageData(size, size); | |
var height = 1.5; | |
var levels = Math.log(size) / Math.log(2); | |
for (var i = 0; i < levels; i++) { | |
var output = []; | |
height /= 2; | |
var len = data.length * 2 - 1; | |
for (var x = 0; x < len; x++) { | |
var a = []; | |
output.push(a); | |
for (var y = 0; y < len; y++) { | |
var x1 = (x / 2) | 0, | |
y1 = (y / 2) | 0, | |
x2 = (x / 2 + .5) | 0, | |
y2 = (y / 2 + .5) | 0; | |
var val = data[x1][y1] + data[x1][y2] + data[x2][y1] + data[x2][y2]; | |
a.push(val * 0.25 + (random((x % (len - 1) + 1) * (y % (len - 1) + 1) * seed) - 0.5) * height); | |
if (i == levels - 1) { | |
var j = (y * size + x) * 4; | |
imgData.data[j] = imgData.data[j + 1] = imgData.data[j + 2] = output[x][y] * 255; | |
imgData.data[j + 3] = 255; | |
} | |
} | |
} | |
data = output; | |
} | |
ctx.putImageData(imgData, 0, 0); | |
return canvas; | |
}; | |
document.body.appendChild(diamondSquare(512, 9)); | |
</script> | |
</body> | |
</html> |
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hey men i have a issue but i new in github you cant draw a cartesian coordinates in your d3 js example http://bl.ocks.org/supereggbert/aff58196188816576af0 i search info for this but i not find it sorry for my english
if you known a one way for this please help me is for a school work thanks for your time
regards.
Mario Castillo