Scraping links from images using selenium

test.py

from selenium import webdriver
from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC

def search_by_image(image_path):
    driver = webdriver.Chrome()
    try:
        driver.get('https://images.google.com/')
        search_by_image_button = WebDriverWait(driver, 3).until(
            EC.presence_of_element_located((By.CLASS_NAME, 'Gdd5U'))
        )
        search_by_image_button.click()

        upload_input = WebDriverWait(driver, 10).until(
            EC.presence_of_element_located(
                (By.CSS_SELECTOR, 'input[type="file"]'),
            )
        )
        upload_input.send_keys(image_path)

        results_div = WebDriverWait(driver, 10).until(
            EC.presence_of_element_located((By.CLASS_NAME, 'aah4tc'))
        )

        all_links = results_div.find_elements(
            By.CSS_SELECTOR, '.G19kAf.ENn9pd > .Vd9M6 > a'
        )
        if len(all_links) == 0:
            print("Cannot get the search results.")
            return

        for link in all_links:
            print(
                f"{link.get_attribute('aria-label')}: {link.get_attribute('href')}"
            )

    except Exception as e:
        print(f"An error occurred: {e}")

    finally:
        driver.quit()

image_path = "city of tears.jpg"
search_by_image(image_path)