soalgojek

""" def f(arr1, arr2):
    k = arr2[3]
    ct = 0
    while k > arr2[2]-1: 
        if (arr1[k] <=  arr2[1] and not arr1[k] <= arr2[0]):
            ct = ct + 1 
        k = k - 1
    return ct 


if __name__ == "__main__":
    x = [11,10,10,5,10,15,20,10,7,11]
    soal1 = [8,18,3,6]
    soal2 = [10,20,0,9]
    soal3 = [8,18,6,3]
    soal4 = [20,10,0,9]
    soal5 = [6,7,8,8]
    kumpulan = [soal1, soal2, soal3, soal4, soal5]
    for soal in kumpulan: 
        print(f(x, soal))    
    
"""

##################################################

def g(str): 
    i = 0
    new_str = ""
    while i < len(str) -1: 
        new_str = new_str + str[i+1]
        i = i+1
    return new_str


def f(str): 
    if len(str) == 0: 
        return ""
    elif len(str) == 1:
        return str
    else: 
        return (f(g(str)) + str[0])


def h(n, str): 
    i= 0
    while n != 1: 
        i+=1
        # print(f'{n}')
        if n%2 == 0: 
            n = n/2
        else: 
            n = 3*n + 1
        str = f(str)
    print(f'diulang {i} kali')
    return str

def pow(x,y): 
    if y == 0: 
        return 1
    else: 
        return x**y

def fast_power(base, power):
    """
    Returns the result of a^b i.e. a**b
    We assume that a >= 1 and b >= 0

    Remember two things!
     - Divide power by 2 and multiply base to itself (if the power is even)
     - Decrement power by 1 to make it even and then follow the first step
    """

    result = 1
    while power > 0:
        # If power is even
        if power % 2 == 0:
            # Divide the power by 2
            power = power // 2
            # Multiply base to itself
            base = base * base
        else:
            # Decrement the power by 1 and make it even
            power = power - 1
            # Take care of the extra value that we took out
            # We will store it directly in result
            result = result * base

            # Now power is even, so we can follow our previous procedure
            power = power // 2
            base = base * base

    return result
print(g('fruits'))
print(f('asyu'))
hasil = []
for i in [1,2,5,fast_power(2,1000000000000000), fast_power(2, 9831050005000007)]:
    print(f"sekarang {i}. {h(i,'fruits')} ")
    print('')