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JS store accounting exercise - solution
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/* | |
STORE ACCOUNTING | |
We are writing a program module for an online shop that processes purchases. | |
The program receives the sold items as an array of objects; each object | |
contains the name of the item, its price and its category (see below). | |
*/ | |
const items = [ | |
{ product: "Premier Housewives Stainless Steel Toolset", price: 19.97, category: "homeware" }, | |
{ product: "iChinchin Women's Long Sleeve T Shirt", price: 15.99, category: "clothing" }, | |
{ product: "U-Design Toothbrush Holder Set", price: 10.55, category: "homeware" }, | |
{ product: "Elgar 400W Hand Mixer", price: 25.99, category: "appliances" }, | |
{ product: "Great Gatsby White and Gold Kettle", price: 49.99, category: "homeware" }, | |
{ product: "AM Bristol Men's Fitted Boxers", price: 24.99, category: "clothing" }, | |
{ product: "Disnoy Brittle Small Cookie Jar", price: 10.01, category: "homeware" }, | |
{ product: "Oreal-C Cross Action Electric Toothbrush", price: 22.19, category: "appliances" }, | |
{ product: "Wrundole Designs Duck Wall Clock", price: 34.50, category: "homeware" }, | |
{ product: "RuralComfort Dressing Gown for Men", price: 26.99, category: "clothing" }, | |
]; | |
// 1. Print the names and the number (the count) of all sold homeware accessories. | |
// Solution 1 (procedural) | |
const homewareProducts = []; | |
let homewareCount = 0; | |
for (const item of items) { | |
if (item.category === "homeware") { | |
homewareProducts.push(item.product); | |
homewareCount++; | |
} | |
} | |
console.log( | |
`1/1 - Homeware products: ${homewareCount} (${homewareProducts.join(", ")})` | |
); | |
// Solution 2 (functional) | |
const homewareProducts2 = items.filter( | |
item => item.category === "homeware" | |
).map( | |
item => item.product | |
); | |
const homewareCount2 = homewareProducts2.length; | |
console.log( | |
`1/2 - Homeware products: ${homewareCount2} (${homewareProducts2.join(", ")})` | |
); | |
// 2. Print the total revenue (the sum of the prices of all sold items). | |
// Solution 1 (procedural) | |
let revenue = 0; | |
for (const item of items) { | |
revenue += item.price; | |
} | |
const roundedRevenue = revenue.toFixed(2); | |
console.log(`2/1 - Total revenue: £${roundedRevenue}`); | |
// Solution 2 (functional) | |
const revenue2 = items.reduce( | |
(revenue, item) => revenue + item.price, 0 | |
).toFixed(2); | |
console.log(`2/2 - Total revenue: £${revenue2}`); | |
// 3. Print the average price of the items. Make sure that the price is | |
// expressed in pounds and pence (is rounded to 2 decimal points). | |
const averagePrice = (revenue / items.length).toFixed(2); | |
console.log(`3 - Average price: £${averagePrice}`); | |
// 4. Print the name of the most expensive product. | |
// Solution 1 (procedural) | |
let mostExpensiveItem = items[0]; | |
for (let i = 1; i < items.length; i++) { | |
if (items[i].price > mostExpensiveItem.price) { | |
mostExpensiveItem = items[i]; | |
} | |
} | |
const mostExpensiveProduct = mostExpensiveItem.product; | |
console.log(`4/1 - The most expensive product: ${mostExpensiveProduct}`); | |
// Solution 2 (functional) | |
const mostExpensiveProduct2 = items.reduce( | |
(mostExpensiveItem, item) => | |
item.price > mostExpensiveItem.price ? item : mostExpensiveItem | |
).product; | |
console.log(`4/2 - The most expensive product: ${mostExpensiveProduct2}`); |
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