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Naive implementation of Unix Timestamp to DateTime conversion
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typedef struct _DateTime { | |
uint16_t year; | |
uint8_t month; | |
uint8_t day; | |
uint8_t hour; | |
uint8_t minute; | |
uint8_t second; | |
} DateTime; | |
uint8_t monthDays[] = {31, 28, 31, 30, 31, 30, 31, 31, 30, 31, 30, 31}; | |
void datetime_update(uint32_t time, DateTime* dt) { | |
uint32_t days = (time / 86400); | |
dt->year = 1970; | |
dt->month = 1; | |
dt->day = 1; | |
while(1) { // rewrite this! | |
char leap_year = (dt->year % 4) == 0; | |
for(int i = 0; i < 12 ;i++) { | |
uint8_t days_in_month = monthDays[i]; | |
if(i == 1 && leap_year) { // February of leap year | |
days_in_month++; | |
} | |
if(days < days_in_month) { | |
dt->day = days + 1; | |
days = 0; | |
break; | |
} | |
days -= days_in_month; | |
dt->month++; | |
} | |
if(days == 0) { | |
break; | |
} | |
dt->month = 1; | |
dt->year++; | |
} | |
uint32_t seconds = (time % 86400); | |
dt->hour = seconds / 3600; | |
dt->minute = (seconds % 3600) / 60; | |
dt->second = (seconds % 3600) % 60; | |
} | |
int main() { | |
init_hw(); | |
PWR_BackupAccessCmd(ENABLE); // ugly ass construction. Time counter is write protected. | |
RTC_WaitForLastTask(); | |
RTC_SetCounter(1375982740); | |
RTC_WaitForLastTask(); | |
PWR_BackupAccessCmd(DISABLE); | |
DateTime dt; | |
while(1) { | |
uint32_t time = RTC_GetCounter(); // unix timestamp | |
datetime_update(time, &dt); | |
printf("Time is %d - %d/%02d/%02d %02d:%02d:%02d!\n", time, dt.year, dt.month, dt.day, dt.hour, dt.minute, dt.second); | |
delay_ms(1000); | |
} | |
} |
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I have checked this code. Not working properly.
I gave this 1622472218 timestamp. The converted result is : 14:43:38 2-4-2026 but it should be 14:43:38 31-5-2021