Created
May 26, 2016 22:34
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class BadNeighbours: | |
def maxDonations(self, donations): | |
L = len(donations) | |
if L < 3: | |
return max(donations) | |
# memo1[L-2] will have maximum value of donations which | |
# *may* include the first neighbour (therefore cannot include | |
# the last neighbour) | |
# memo2[L-1] will have the maximum value of donations | |
# which do not include the first neighbour (and therefore | |
# can include the last neighbour) | |
memo1, memo2 = [0]*L, [0]*L | |
memo1[0], memo2[0] = donations[0], 0 | |
memo1[1], memo2[1] = donations[1], donations[1] | |
memo1[2], memo2[2] = donations[2] + memo1[0], donations[2] + memo2[0] | |
for n in range(3, L): | |
memo1[n] = max(memo1[n-2] + donations[n], memo1[n-3] + donations[n]) | |
memo2[n] = max(memo2[n-2] + donations[n], memo2[n-3] + donations[n]) | |
return max(memo1[L-2], memo2[L-1]) |
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