04. 元素記号

nlp100_2015_04.py

#!/usr/bin/env python

s = 'Hi He Lied Because Boron Could Not Oxidize Fluorine. New Nations Might Also Sign Peace Security Clause. Arthur King Can.'

result = {}

# enumerate()でループの回数を取得する
for i, elem in enumerate(s.split(), start=1):
    # 指定番号かどうか
    if {i} & {1, 5, 6, 7, 8, 9, 15, 16, 19}:
        result[elem[0]] = i
    else:
        result[elem[0:2]] = i

# 結果出力
for items in result.items():
    print(items)