You are given a binary array nums. You can do the following operation on the array any number of times (possibly zero): Choose any 3 consecutive elements from the array and flip all of them. Flipping an element means changing its value from 0 to 1,

minOperations.js

/**
 * @param {number[]} nums
 * @return {number}
 */
var minOperations = function(nums) {
    let count = 0; // Initialize the counter for the number of flips

    // Helper function to flip a single element at index i
    function flip(i) {
        nums[i] = nums[i] === 0 ? 1 : 0; // Toggle the element (0 -> 1, 1 -> 0)
    }

    // Traverse the array, stopping at the third-to-last element
    for (let i = 0; i < nums.length - 2; i++) {
        // If the current element is 0, perform a flip operation on the group of 3
        if (nums[i] === 0) {
            count++; // Increment the flip counter
            flip(i); // Flip the current element
            flip(i + 1); // Flip the next element
            flip(i + 2); // Flip the element after that
        }
    }

    // If there are still any 0s left in the array, return -1 (impossible case)
    if (nums.includes(0)) {
        return -1;
    }

    // Otherwise, return the total number of flip operations performed
    return count;
};