You are given a 2D 0-indexed integer array dimensions. For all indices i, 0 <= i < dimensions.length, dimensions[i][0] represents the length and dimensions[i][1] represents the width of the rectangle i. Return the area of the rectangle having the l

areaOfMaxDiagonal.js

/**
 * Returns the area of the rectangle with the longest diagonal.
 * If multiple rectangles share the longest diagonal, returns the one with the largest area.
 *
 * @param {number[][]} dimensions - Array of [length, width] pairs for each rectangle.
 * @return {number} - Area of the rectangle with the longest diagonal.
 */
var areaOfMaxDiagonal = function(dimensions) {
    let maxDiagonalSq = 0; // Stores the longest diagonal squared (avoids using Math.sqrt)
    let maxArea = 0;       // Stores the area of the rectangle with the longest diagonal

    for (let i = 0; i < dimensions.length; i++) {
        const [length, width] = dimensions[i];

        // Calculate squared diagonal: length² + width²
        const diagonalSq = length * length + width * width;

        // Calculate area: length × width
        const area = length * width;

        // Update if this rectangle has a longer diagonal,
        // or same diagonal but larger area
        if (
            diagonalSq > maxDiagonalSq ||
            (diagonalSq === maxDiagonalSq && area > maxArea)
        ) {
            maxDiagonalSq = diagonalSq;
            maxArea = area;
        }
    }

    return maxArea;
};