Given an array nums of integers, return how many of them contain an even number of digits.

findNumbers.js

/**
 * @param {number[]} nums
 * @return {number}
 */
var findNumbers = function(nums) {
    let count = 0; // Initialize a counter for numbers with an even number of digits

    for (let num of nums) { // Loop through each number in the array
        // Convert the number to a string (absolute value to handle negatives) and get its length
        let digitCount = Math.abs(num).toString().length;

        // If the length is even, increase the counter
        if (digitCount % 2 === 0) {
            count++;
        }
    }

    return count; // Return the total count of numbers with an even number of digits
};