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December 10, 2015 17:58
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# Above are some results from the a matrix of a | |
# trivariate cholesky with the above diag cells filled in | |
A = matrix(nrow = 3, byrow = T, c(.71, -.28, .15, -.28, .61, -.38, .15, -.38, .000001)) | |
[,1] [,2] [,3] | |
[1,] 0.71 -0.28 1.5e-01 | |
[2,] -0.28 0.61 -3.8e-01 | |
[3,] 0.15 -0.38 1.0e-06 | |
# Yeah... so that's wrong. that's the lower a matrix. | |
# So let's get back to that lower and start again: | |
a <- A # make a copy | |
a[upper.tri(a)] <- 0 # empty the upper triangle, and have a look at what we've got | |
round(a,2) | |
[,1] [,2] [,3] | |
[1,] 0.71 0.00 0 | |
[2,] -0.28 0.61 0 | |
[3,] 0.15 -0.38 0 | |
# Now big A is: | |
A = a %*% t(a) # see how var three now has some variance... | |
[,1] [,2] [,3] | |
[1,] 0.5041 -0.1988 0.1065 | |
[2,] -0.1988 0.4505 -0.2738 | |
[3,] 0.1065 -0.2738 0.1669 | |
# And then: | |
I = diag(3) | |
rg = solve(sqrt(I * A)) %&% A | |
round(rg,2) | |
[,1] [,2] [,3] | |
[1,] 1.00 -0.42 0.37 | |
[2,] -0.42 1.00 -1.00 | |
[3,] 0.37 -1.00 1.00 |
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