Created
June 28, 2020 06:18
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Guess the data structure kattis problem
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import sys | |
for i in sys.stdin: | |
if i.rstrip() == '': | |
break | |
i = int(i) | |
s = [] | |
q = [] | |
pq = [] | |
p = [1]*3 | |
for j in range(i): | |
a, b = list(map(int, input().split())) | |
if a == 1: | |
s.append(b) | |
q.append(b) | |
pq.append(b) | |
else: | |
if p[0] == 1: | |
if s: | |
if s[len(s)-1] != b: | |
p[0] = 0 | |
else: | |
del s[len(s)-1] | |
else: | |
p[0] = 0 | |
if p[1] == 1: | |
if q: | |
if q[0] != b: | |
p[1] = 0 | |
else: | |
del q[0] | |
else: | |
p[1] = 0 | |
if p[2] == 1: | |
if pq: | |
if max(pq) != b: | |
p[2] = 0 | |
else: | |
del pq[pq.index(max(pq))] | |
else: | |
p[2] = 0 | |
count = sum(p) | |
if count > 1: | |
print('not sure') | |
elif count == 0: | |
print('impossible') | |
else: | |
if p[0] == 1: | |
print('stack') | |
else: | |
print('queue') if p[1] == 1 else print('priority queue') |
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