Created
June 14, 2017 17:16
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電網導作業3
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| #include <stdio.h> | |
| #include <string.h> | |
| void init(int d[9][9]) | |
| { for (int i = 0; i < 9; ++i) | |
| for (int j = 0; j < 9; ++j) | |
| d[i][j] = (i == j) ? 0 : -1; | |
| d[0][1] = 4; d[0][7] = 8; | |
| d[1][0] = 4; d[1][7] = 11; d[1][2] = 8; | |
| d[2][1] = 8; d[2][8] = 2; d[2][3] = 7; d[2][5] = 4; | |
| d[3][2] = 7; d[3][4] = 9; d[3][5] = 14; | |
| d[4][3] = 9; d[4][5] = 10; | |
| d[5][2] = 4; d[5][3] = 14; d[5][4] = 10; d[5][6] = 2; | |
| d[6][5] = 2; d[6][7] = 1; d[6][8] = 6; | |
| d[7][0] = 8; d[7][1] = 11; d[7][8] = 7; d[7][6] = 1; | |
| d[8][2] = 2; d[8][6] = 6; d[8][7] = 7; | |
| } | |
| void print(int d[9][9]) | |
| { for (int i = 0; i < 9; ++i) | |
| { printf("D%d(0, 1, 2, 3, 4, 5, 6, 7, 8, 9) = (", i); | |
| for (int j = 0; j < 9; ++j) | |
| { if (j) printf(", "); | |
| if (d[i][j] == -1) | |
| printf("\u221E"); | |
| else | |
| printf("%d", d[i][j]); | |
| } | |
| printf(")\n"); | |
| } | |
| } | |
| void solve(int e[9][9], int d[9][9]) // Bellman-Ford | |
| { | |
| for (int i = 0; i < 9; ++i) | |
| for (int j = 0; j < 9; ++j) | |
| d[i][j] = (i == j) ? 0 : -1; | |
| for (int u = 0; u < 9; ++u) // For each node | |
| { for (int t = 0; t < 9-1; ++t) | |
| for (int i = 0; i < 9; ++i) | |
| for (int j = 0; j < 9; ++j) | |
| if (e[i][j] != -1 && d[u][i] != -1) | |
| { if (d[u][j] == -1 || d[u][i] + e[i][j] < d[u][j]) | |
| { | |
| d[u][j] = d[u][i] + e[i][j]; | |
| } | |
| } | |
| } | |
| } | |
| void dv(int e[9][9], int d[9][9]) // Distance Vector simulation | |
| { | |
| int prev_d[9][9]; | |
| for (int i = 0; i < 9; ++i) | |
| for (int j = 0; j < 9; ++j) | |
| prev_d[i][j] = d[i][j] = e[i][j]; | |
| int update = 0; | |
| do { | |
| update = 0; | |
| for (int u = 0; u < 9; ++u) | |
| { for (int v = 0; v < 9; ++v) d[u][v] = prev_d[u][v]; | |
| for (int v = 0; v < 9; ++v) | |
| if (e[u][v] > 0) // Not myself, and my neighbour | |
| { for (int k = 0; k < 9; ++k) // Only update by information passed by neighbour | |
| if (prev_d[v][k] != -1) | |
| { if (d[u][k] == -1 || d[u][v] + prev_d[v][k] < d[u][k]) | |
| { | |
| d[u][k] = d[u][v] + prev_d[v][k]; | |
| update = 1; | |
| } | |
| } | |
| } | |
| } | |
| for (int i = 0; i < 9; ++i) | |
| for (int j = 0; j < 9; ++j) | |
| prev_d[i][j] = d[i][j]; | |
| } | |
| while(update); | |
| } | |
| int main() | |
| { | |
| int e[9][9], d[9][9], k[9][9]; | |
| init(e); | |
| print(e); | |
| solve(e, d); | |
| printf("Solved:\n"); | |
| print(d); | |
| dv(e, k); | |
| printf("Hello\n"); | |
| print(k); | |
| return 0; | |
| } |
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