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@tetsuok
Created April 2, 2012 01:58
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An answer of the exercise: Loops and Functions on a tour of Go
package main
import (
"fmt"
"math"
)
const Delta = 0.0001
func isConverged(d float64) bool {
if d < 0.0 {
d = -d
}
if d < Delta {
return true
}
return false
}
func Sqrt(x float64) float64 {
z := 1.0
tmp := 0.0
for {
tmp = z - (z * z - x) / 2 * z
if d := tmp - z; isConverged(d) {
return tmp
}
z = tmp
}
return z
}
func main() {
attempt := Sqrt(2)
expected := math.Sqrt(2)
fmt.Printf("attempt = %g (expected = %g) error = %g\n",
attempt, expected, attempt - expected)
}
@ankitkumar5422
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package main

import (
"fmt"
"math"
)

func Sqrt(x float64) float64 {
z:=1.0

for n:= 1;n < 10;n++ {
	z = z - ((z*z - x) / (2*z))
}
return z

}

func main() {
y := 169.
fmt.Println(Sqrt(y))
fmt.Println(math.Sqrt(y))
}

@vishwa5854
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func Sqrt(x float64) float64 {
var z, tmp float64 = 1.0, 0.
for ; math.Abs(z - tmp) >= 1e-8 ; z, tmp = z - (zz-x)/(2z), z {}
return z
}

@masiunas
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package main

import (
"fmt"
)

func Sqrt(x float64) float64 {
z := float64(1)
for i := 1; i <= 10; i++ {
nextZ := z - (zz-x)/(2z)
if nextZ == z {
return z
} else {
z = nextZ
fmt.Println(z, i)
}
}
return z
}

func main() {
p := 2.0
fmt.Println(Sqrt(p))
}

@NATSUNOAME1337
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package main

import (
"fmt"
"math"
)

func Sqrt(x float64) float64 {
z := 1.0
iterations := 0

for i := 0; i <= 100; i++ {

	z -= (z*z - x) / (2 * z)
	iterations += 1

	if z == math.Sqrt(x) {
		break
	}
}
fmt.Println(z, "iterations: ", iterations)
return z

}

func main() {
var x float64 = 102444
fmt.Println("Guess: ", Sqrt(x))
fmt.Println("Math module: ", math.Sqrt(x))
}

@filipcvejic
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filipcvejic commented Apr 29, 2025

package main

import (
	"fmt"
	"math"
)

func Sqrt(x float64) float64 {
	prev, z := 0.0, 1.0
	
	for math.Abs(prev - z) > 1e-3 {
		prev = z
		z -= (z*z - x) / (2*z)
	}
	
	return z
}

func main() {
	n := 2.0
	g := Sqrt(n)
	a := math.Sqrt(n)
	d := math.Abs(g - a)
	fmt.Printf("Guessed: %f  Actual: %f  Delta: %f\n", g, a, d)
}

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