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July 4, 2017 07:39
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Transform a function from `R f(P ... ps)` to `std::optional<R> f(std::optional<P> ... ps)` and use it monadic style. needs C++17.
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#include <iostream> | |
#include <optional> | |
/// library part | |
template <typename R, typename ... P> | |
auto lift_optional(R (*f)(P ... ps)) | |
{ | |
return [f](std::optional<P> ... xs) -> std::optional<R> { | |
if ((xs && ...)) { | |
return {f(*(xs)...)}; | |
} else { | |
return {}; | |
} | |
}; | |
} | |
template <typename T> | |
std::ostream& operator<<(std::ostream &os, const std::optional<T> &mt) | |
{ | |
if (mt) { | |
return os << "Just " << *mt; | |
} else { | |
return os << "Nothing"; | |
} | |
} | |
/// user code | |
int f(int a, int b) | |
{ | |
return a + b; | |
} | |
int g(int a) | |
{ | |
return 2 * a; | |
} | |
auto mf = lift_optional(f); | |
auto mg = lift_optional(g); | |
int main() | |
{ | |
std::cout << mg(mf({1}, {})) << '\n'; | |
std::cout << mg(mf({1}, {2})) << '\n'; | |
} |
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