Created
February 12, 2023 02:10
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heuristic sudoku solution
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def solve(grid): | |
empty_cell = find_empty_cell(grid) | |
if not empty_cell: | |
return grid | |
row, col = empty_cell | |
possible_numbers = get_possible_numbers(grid, row, col) | |
for num in possible_numbers: | |
grid[row][col] = num | |
solved_grid = solve(grid) | |
if solved_grid: | |
return solved_grid | |
grid[row][col] = 0 | |
return None | |
def find_empty_cell(grid): | |
min_possible_numbers = float("inf") | |
empty_cell = None | |
for row in range(9): | |
for col in range(9): | |
if grid[row][col] == 0: | |
possible_numbers = len(get_possible_numbers(grid, row, col)) | |
if possible_numbers < min_possible_numbers: | |
min_possible_numbers = possible_numbers | |
empty_cell = (row, col) | |
return empty_cell | |
def get_possible_numbers(grid, row, col): | |
used_numbers = set(grid[row][i] for i in range(9)) | \ | |
set(grid[i][col] for i in range(9)) | |
row_start = (row // 3) * 3 | |
col_start = (col // 3) * 3 | |
used_numbers |= {grid[row_start + i][col_start + j] for i in range(3) for j in range(3)} | |
return [num for num in range(1, 10) if num not in used_numbers] |
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