Created
May 7, 2017 00:20
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disjoint sets meio torto escrito em Python (o que eu fiz em C eh que eh o bicho!)
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sets = {} | |
setsRanked = {} | |
def makeSet(x): | |
sets[x] = set([x]) | |
def find(x): | |
for representative,subset in sets.iteritems(): | |
if x in subset: | |
return representative | |
return None | |
def union(x, y): | |
xRepresentative = find(x) | |
yRepresentative = find(y) | |
sets[yRepresentative] = sets[yRepresentative].union(sets[xRepresentative]) | |
del sets[xRepresentative] | |
def makeSetWithRank(x): | |
setsRanked[x] = [set([x]), 0] | |
# naum faz path compression na real, foi soh para criar um outro find pros setsRanked | |
def findWithPathCompression(x): | |
for representative,subsetRanked in setsRanked.iteritems(): | |
if x in subsetRanked[0]: | |
return representative | |
return None | |
def unionByRank(x, y): | |
xRepresentative = findWithPathCompression(x) | |
yRepresentative = findWithPathCompression(y) | |
if xRepresentative != yRepresentative: | |
if setsRanked[xRepresentative][1] < setsRanked[yRepresentative][1]: | |
setsRanked[xRepresentative][0] = setsRanked[xRepresentative][0].union(setsRanked[yRepresentative][0]) | |
del setsRanked[yRepresentative] | |
elif setsRanked[xRepresentative][1] > setsRanked[yRepresentative][1]: | |
setsRanked[yRepresentative][0] = setsRanked[yRepresentative][0].union(setsRanked[xRepresentative][0]) | |
del setsRanked[xRepresentative] | |
else: | |
setsRanked[yRepresentative][0] = setsRanked[yRepresentative][0].union(setsRanked[xRepresentative][0]) | |
setsRanked[yRepresentative][1] += 1 | |
del setsRanked[xRepresentative] |
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