clos.sh

#/bin/bash
# clos - count lines of semicolons
# A simple utility that counts the number of semicolons in the supplied files
#  NOT the number of lines with semicolons as the name implies, sorry about that

## MIT License
## 
## Copyright (c) 2019 Aleksander B. Birkeland
## 
## Permission is hereby granted, free of charge, to any person obtaining a copy
## of this software and associated documentation files (the "Software"), to deal
## in the Software without restriction, including without limitation the rights
## to use, copy, modify, merge, publish, distribute, sublicense, and/or sell
## copies of the Software, and to permit persons to whom the Software is
## furnished to do so, subject to the following conditions:
## 
## The above copyright notice and this permission notice shall be included in all
## copies or substantial portions of the Software.
## 
## THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND, EXPRESS OR
## IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF MERCHANTABILITY,
## FITNESS FOR A PARTICULAR PURPOSE AND NONINFRINGEMENT. IN NO EVENT SHALL THE
## AUTHORS OR COPYRIGHT HOLDERS BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER
## LIABILITY, WHETHER IN AN ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM,
## OUT OF OR IN CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
## SOFTWARE.

if [[ $# -eq "0" ]]; then
	echo "Usage: $0 <file>..."
	exit
fi

semicolons=0
table=""

table="file|count"

for file in $@; do
	if ! test -e "$file"; then
		echo "$0: $file: No such file or directory"
	fi
	if ! test -f "$file"; then
		continue
	fi

	lines=$(grep -o ";" $file | wc -l)
	((semicolons += lines))
	entry="\n$file|$lines"
	table="$table$entry"
done

table="$table|\n"
table="${table}total|$semicolons\n"

echo -e $table | column -t -s "|"