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@theleoborges
Last active August 29, 2015 14:20
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(async
(let [a (await (async-task-a))
b (await (async-task-b))
c (await (async-task-c (* a b)))]
(+ a b c)))
;; whish is equivalent to:
(async
(let [a (await (async-task-a))
b (await (async-task-b))]
(+ a
b
(await (async-task-c (* a b))))))
;; async blocks return futures
@jedws
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jedws commented May 6, 2015

can you describe what this does?

it seems to create an async-task that simply awaits the first two, and then awaits that. if so, that seems like an undesirable thing to want to do, so I assume this does something else entirely :-)

@karlmikko
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This is quite nice!

@theleoborges
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@jed,

I've updated the example to perhaps make it slightly clearer. The two are equivalent and are an alternative way of writing flatmap/map;

(flatmap (async-task-a)
         (fn [a]
           (flatmap (async-task-b)
                    (fn [b]
                      (map (async-task-c (* a b)) 
                           (fn [c]
                             (+ a b c)))))))

Or this do-notation:

(do [a (async-task-a)
     b (async-task-b)
     c (async-task-c (* a b))]
    (return (+ a b c)))

It just allows you to write sync-looking async code without necessarily having to bind the result of intermediate values if it's not necessary. (in haskell one could also use liftA to the same effect).

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