function to return true if the string can be broken down to incrementing sets of integers

algorithm.js

/**
 * Write a function to return true if the string can be broken down to incrementing sets of integers
 * no negative >= 1
 * "" => false
 * "1" > false
 * "1315" => ? => false
 * "54" => false
 * "1234" => "1" + "2" + "3" + "4" => true
 * "91011" => "9" + "10" + "11" => true
 * "5556" => "55" + "56" => true
 * "9991000" => "999" + "1000" => true
 * 
 * cc Problem by Simon Lim  
 */

/**
 *  created by Theophilus Omoregbee <theo4u@ymail.com>
 *
 *      Hurray finally gotten it
 */

/////// test cases ///
// let input = "91011";
//  let input  = "5556";
//  let input  = "1234";
// let input = "1315";
// let input = "1314";
// let input = "99999999100000000";
// let input = "998999";
let input = "99100101";

let c = input.split('');// this is used and can be altered when our programming is running

let original = input.split(''); // just to keep track of the original array

// parse it to be number here
let realMultiple = 1;
for (let i = 0; i < c.length; i++) {

    c[i] = restructureFirstElement(realMultiple);


    let d = [parseInt(c[i])]; // add to our array to push too when any creteria is correct

    let s = "";
    let check = true;
  
    for (let j = i + 1; j < c.length; j++) {
        s += c[j];

        if ((d[d.length - 1] - parseInt(s)) === -1) {
            d.push(parseInt(s));
            i = j + 1;
            s = '';
            // console.log("C", c[i], j);
            check = true;
        } else {
            // console.log("not same", d[d.length - 1], parseInt(s), i, j);
            check = false;
        }

        console.log("d", d);
    }

    realMultiple++; // increase multiple here to next tens


    if (check && d.length > 1) {
        console.log("Yippee correct", check);
    } else {
        check = false
    }


}

/**
 * increase the first element if its tens or 100s or units
 * @param multiple
 * @returns {string}
 */
function restructureFirstElement(multiple) {
    let value = "";
    for (let i = 0; i < multiple; i++) {
        value += original[i];
    }

    return value;
}