Created
July 5, 2012 23:49
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dynamic programming generic 0-1 knapsack problem solver
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def solve_knapsack(items, maxcost, cost=lambda n:n, value=None): | |
""" | |
Generic dynamic-programming knapsack problem solver. Takes time | |
O(len(items) * maxcost), so it can be helpful to reduce the costs | |
and maxcost by the greatest common divisor if possible. Costs for | |
all items must be nonnegative integers. | |
Returns the set of items the sum of whose costs does not exceed | |
maxcost, and the sum of whose values is otherwise maximal. | |
""" | |
if value is None: | |
value = cost | |
items_ann = [(item, cost(item), value(item)) for item in items] | |
table = [[0] * (maxcost + 1) for row in xrange(len(items) + 1)] | |
for table_index, (i, cost, val) in enumerate(items_ann): | |
lastcost = table[table_index] | |
thiscost = table[table_index + 1] | |
for cap_index in xrange(maxcost + 1): | |
if cost > cap_index: | |
newcost = lastcost[cap_index] | |
else: | |
newcost = max(lastcost[cap_index], val + lastcost[cap_index - cost]) | |
thiscost[cap_index] = newcost | |
result = [] | |
ctr = maxcost | |
for table_index, (item, cost, val) in reversed(list(enumerate(items_ann))): | |
if table[table_index + 1][ctr] != table[table_index][ctr]: | |
result.append(item) | |
ctr -= cost | |
return result[::-1] |
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