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@theresajayne
Created July 1, 2011 10:15
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context + class
<?xml version="1.0" encoding="UTF-8"?>
<web-app version="2.5" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd">
<servlet>
<servlet-name>getcmyk</servlet-name>
<servlet-class>uk.co.inbrand.getcmyk.GetCMYK</servlet-class>
</servlet>
<servlet-mapping>
<servlet-name>getcmyk</servlet-name>
<url-pattern>/getcmyk/*</url-pattern>
<url-pattern>/*</url-pattern>
</servlet-mapping>
<session-config>
<session-timeout>
30
</session-timeout>
</session-config>
<welcome-file-list>
<welcome-file>index.jsp</welcome-file>
</welcome-file-list>
</web-app>
class file
/*
* Take in RGB url on the input and convert it to CMYK returning it as a binary feed
*/
package uk.co.inbrand.getcmyk;
import java.io.ByteArrayInputStream;
import java.io.IOException;
import java.net.MalformedURLException;
import java.net.URL;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
/**
*
* @author Theresa
*/
public class GetCMYK extends HttpServlet {
private String myurl = null;
public void get(HttpServletRequest request, HttpServletResponse response) {
//WE need to get the url in from the passed in parameters
myurl = request.getParameter("url");
if (myurl==null ) {
System.err.println("No parameter passed");
}
String profile="file://c:/inbrand-1.0/CMYK.pf";
byte[] rgb = null;
try {
URL myurlUrl = new URL(myurl);
myurlUrl.getContent();
myurlUrl.openConnection();
ByteArrayInputStream instr = (ByteArrayInputStream)myurlUrl.openStream();
instr.read(rgb);
CMYKSave save = new CMYKSave();
save.getcmyk(profile, rgb);
}catch(MalformedURLException mue) {
} catch(IOException ioe) {
}
}
public void post(HttpServletRequest request, HttpServletResponse response) {
}
}
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