Created
May 8, 2011 04:15
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"""Solve the 1D diffusion equation using CN and finite differences.""" | |
from time import sleep | |
import numpy as np | |
import matplotlib.pyplot as plt | |
import networkx as nx | |
# The total number of nodes | |
nodx = 3 | |
nody = 3 | |
nodz = 3 | |
nnodes = nodx*nody*nodz | |
# The total number of times | |
ntimes = 500 | |
# The time step | |
dt = 0.5 | |
# The diffusion constant | |
D = 0.1 | |
# The spatial mesh size | |
h = 1.0 | |
G = nx.grid_graph(dim=[nodx,nody,nodz]) | |
L = np.matrix(nx.laplacian(G)) | |
# The rhs of the diffusion equation | |
rhs = -D*L/h**2 | |
# Setting initial temperature | |
T = 60*np.matrix(np.ones((nnodes,ntimes))) | |
for i in range(nnodes/2): | |
T[i,0] = 0; | |
# Setup the time propagator. In this case the rhs is time-independent so we | |
# can do this once. | |
ident = np.matrix(np.eye(nnodes,nnodes)) | |
pmat = ident+(dt/2.0)*rhs | |
mmat = ident-(dt/2.0)*rhs | |
propagator = np.linalg.inv(mmat)*pmat | |
# Propagate E is for energy conservation | |
E = np.zeros(ntimes) | |
for i in range(ntimes-1): | |
E[i] = sum(T[:,i]) | |
T[:,i+1] = propagator*T[:,i] | |
# To plot 1 time | |
print E[2] | |
print T[:,100] | |
# To plot all times | |
#plt.plot(T) |
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