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April 19, 2026 15:21
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GEnerare submultimi cu 2 for complexitate O(n2^n)
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| /* | |
| for(int i = 1; i <= n; ++i) { | |
| for(int j = 1; j <= n; ++j) { | |
| } | |
| } | |
| O(n^2) | |
| A = {1,2,3}; | |
| Toate submultimile = 2^n = 2^3 = 8 submultimi | |
| Time Complexity O(n 2^n) | |
| 0000 0000 0000 0000 0000 0000 0000 0001 | |
| 1 = 001 {1} | |
| 2 = 010 {2} | |
| 3 = 011 {1,2} | |
| 4 = 100 {3} | |
| 5 = 101 {1,3} | |
| 6 = 110 {3,2} | |
| 7 = 111 {1,2,3} | |
| 8 = 1000 {} | |
| 0000 0000 0000 0000 0000 0000 0000 1000 = 8 | |
| 001 & | |
| 001 | |
| === | |
| 001 | |
| 001 SAU | |
| 010 | |
| === | |
| 011 | |
| */ | |
| //pow(2,n) | |
| public class Subsets { | |
| public static void gen(int n) { | |
| for(int mask = 1; mask<= (1<<n); mask++) { | |
| System.out.print("{"); | |
| for(int i = 0; i < n; i++) { | |
| if((mask & (1<<i)) != 0) { | |
| System.out.print(i + 1 + " "); | |
| } | |
| } | |
| System.out.println("}"); | |
| } | |
| } | |
| //5 = 101 {1,3} | |
| // 101 | |
| // 100 | |
| public static void main(String[] args) { | |
| int n = 3; | |
| gen(n); | |
| } | |
| } |
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