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TSP Traveling Salesman Problem O(n!) complexitate
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| /* | |
| Input: | |
| Numar de noduri si matricea costurilor | |
| 5 | |
| 0 9 0 8 0 | |
| 7 0 1 0 3 | |
| 5 0 0 0 4 | |
| 0 0 6 0 0 | |
| 0 1 0 7 0 | |
| */ | |
| #include <iostream> | |
| #include <climits> | |
| #define FIN "tsp.in" | |
| #define FOUT "tsp.out" | |
| using namespace std; | |
| const int SIZE = 100; | |
| int path[ SIZE ]; | |
| int matrixCosts[ SIZE ][ SIZE ]; | |
| int bestPath[ SIZE ]; | |
| bool used[ SIZE ]; | |
| int nodes, start_node, bestCost = INT_MAX, currentCost; | |
| void printSol() { | |
| cout<<"Costul minim: "<<bestCost<<"\n"; | |
| cout<<"Drumul minim: "; | |
| for(int i = 1; i <= nodes; ++i) { | |
| cout<<bestPath[i]<<" "; | |
| } | |
| cout<<start_node; | |
| } | |
| void saveSol() { | |
| for(int i = 1; i <= nodes; ++i) { | |
| bestPath[i] = path[ i ]; | |
| } | |
| } | |
| void hamilton(int k) { | |
| if( k == nodes + 1 ) { | |
| //check for cycle | |
| if(matrixCosts[path[nodes]][start_node] > 0) { | |
| int totalCost = currentCost + matrixCosts[ path[nodes] ][ start_node ]; | |
| if(totalCost < bestCost) { | |
| bestCost = totalCost; | |
| saveSol(); | |
| } | |
| } | |
| } else { | |
| // 4 | |
| // 1 | |
| //daca nodul nu este folosit | |
| for(int v = 1; v <= nodes; ++v) { | |
| if(!used[ v ] && matrixCosts[ path[k - 1] ][ v ] > 0) { | |
| int newCost = currentCost + matrixCosts[path[k-1] ][ v ]; | |
| //branch and bound | |
| if( newCost >= bestCost ) continue; | |
| path[ k ] = v; | |
| currentCost = newCost; | |
| used[ v ] = true; | |
| hamilton(k + 1); | |
| currentCost = currentCost -matrixCosts[ path[k-1] ][ v ]; | |
| used[ v ] = false; | |
| } | |
| } | |
| } | |
| } | |
| int main(int argc, char const *argv[]) | |
| { | |
| freopen(FIN, "r", stdin); | |
| cin>>nodes; | |
| for(int i = 1; i <= nodes; ++i) { | |
| for(int j = 1; j <= nodes; ++j) { | |
| cin>>matrixCosts[i][j]; | |
| } | |
| } | |
| //matricea costurilor | |
| for(int i = 1; i <= nodes; ++i) { | |
| for(int j = 1; j <= nodes; ++j) { | |
| cout<<matrixCosts[i][j]<<" "; | |
| } | |
| cout<<endl; | |
| } | |
| //nodul de start | |
| start_node = 1; | |
| path[ start_node ] = 1; | |
| //path[5] | |
| //path[4] | |
| //path[3] | |
| //path[2] = | |
| //path[1] = 1 | |
| //marcam nodul de start ca fiind explorat | |
| used[ start_node ] = true; | |
| //apelam functia hamilton cu nodul urmator 2 | |
| hamilton( 2 ); | |
| //afisam solutia | |
| printSol(); | |
| return 0; | |
| } | |
| //Complexitate O(n!) | |
| //gasirea unui ciclu hamiltonian de const minim |
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