Created
December 25, 2022 05:30
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/** | |
* @param {string} s | |
* @return {number} | |
*/ | |
function lengthOfLongestSubstring (s) { | |
// Base cases | |
if (s.length <= 1) | |
return s.length | |
var loop; | |
var subStr; | |
var iterator; | |
var length = 0; | |
// Iterate over the string | |
for (var i = 0; i < s.length; i++) { | |
iterator = i; | |
loop = true; | |
subStr = ''; | |
// Given the current character, iterate over the remaining string to the right of that character | |
while (loop) { | |
subStr += s[iterator]; | |
iterator++; | |
if (subStr.includes(s[iterator]) || iterator >= s.length) { | |
loop = false; | |
if (subStr.length > length) { | |
length = subStr.length; | |
} | |
} | |
} | |
} | |
return length; | |
} | |
lengthOfLongestSubstring("abcabcbb"); // 3 | |
lengthOfLongestSubstring("bbbbb"); // 1 | |
lengthOfLongestSubstring("pwwkew"); // 3 |
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