[PHP] Data Access Object Pattern Example

PatternDAO_User.php

<?php 

abstract class baseDAO{
	private $__connection;
	
	public function __construct(){
		$this->_connectToDB(DB_USER, DB_PASS, DB_HOST, DB_DATABASE);
	}
	
	private function __connectToDB($user, $pass, $host, $database){
		$this->__connection = mysql_connect($host, $user, $pass);
		mysql_select_db($database, $this->__connection);
	}
	
	public function fetch($value, $key = NULL){
		if (is_null($key)){
			$key = $this- > primaryKey;
		}
	
		$sql = "select * from {$this->tableName} where {$key}='{$value}'";
		$results = mysql_query($sql, $this- >__connection);
		$rows = array();
		
		while ($result = mysql_fetch_array($results)) {
			$rows[] = $result;
		}
		return $rows;
	}
	
	public function update($keyedArray){
		$sql = "update {$this->tableName} set ";
		$updates = array();
		
		foreach ($keyedArray as $column=> $value) {
			$updates[] = "{$column}='{$value}'";
		}
		
		$sql .= implode(',', $updates);
		$sql .= "where {$this->primaryKey}='{$keyedArray[$this->primaryKey]}'";
		mysql_query($sql, $this->__connection);
	}
}

class userDAO extends baseDAO{
	protected $_tableName = 'userTable';
	protected $_primaryKey = 'id';
	
	public function getUserByFirstName($name){
		$result = $this->fetch($name, 'firstName');
		return $result;
	}
}


define('DB_USER', 'user');
define('DB_PASS', 'pass');
define('DB_HOST', 'localhost');
define('DB_DATABASE', 'test');

$user = new userDAO();
$userDetailsArray = $user->fetch(1);
$updates = array('id' => 1, 'firstName' => 'aaron');
$user->update($updates);
$allAarons = $user->getUserByFirstName('aaron');
?>

Isnt this just active record?