Created
July 9, 2016 13:59
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Find the index S such that the leaders of the sequences A[0], A[1], ..., A[S] and A[S + 1], A[S + 2], ..., A[N - 1] are the same.
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import java.util.Stack; | |
public class EquiLeader { | |
public int solution(int[] A) { | |
if(A == null || A.length == 0) { | |
return 0; | |
} | |
Stack<Integer> stack = new Stack<>(); | |
for(int i = 0; i < A.length; i++) { | |
if(stack.isEmpty()) { | |
stack.push(A[i]); | |
continue; | |
} | |
if(stack.peek() != A[i]) { | |
stack.pop(); | |
} else { | |
stack.push(A[i]); | |
} | |
} | |
if(stack.isEmpty()) { | |
return 0; | |
} | |
int candidate = stack.pop(); | |
int leaderCounter = 0; | |
for(int i = 0; i < A.length; i++) { | |
if(A[i] == candidate) { | |
leaderCounter++; | |
} | |
} | |
if(leaderCounter <= A.length / 2) { | |
return 0; | |
} | |
int equiLeaders = 0; | |
double currentLeaderCount = 0.0; | |
for(int i = 0; i < A.length; i++) { | |
if(A[i] == candidate) { | |
currentLeaderCount++; | |
} | |
if(currentLeaderCount > (i + 1.0) / 2.0 && leaderCounter - currentLeaderCount > (A.length - 1.0 - i) / 2.0) { | |
equiLeaders++; | |
} | |
} | |
return equiLeaders; | |
} | |
} |
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