Compares a user's input to a list of allowable reponses and returns the keyword.

MultipleChoice.py

def parse_response(multiple_choice, prompt=None):
    """
    Splits a user's input into individual words and searches a list
    of allowable responses for a unique match, then returns the word
    that matches one of the options.

    List comprehension syntax explained for my own reference:
    1. for i in response.split() - breaks every word of response
        into individual strings
    2. if i in multiple_choice - searches for ALL recognized words
        within list of possible keywords
    3. [i for ...] - appends all intersections from the rest of the
        list comprehension to a list

    Arguments
    ---------
    multiple_choice : list or dict
        The options allowed within the user's response. If a dict
        is passed, a list is generated from dict.keys().
    prompt : string
        If not specified, the prompt for user input prints a single
        caret >. A string can be specified to print a more useful
        prompt if need be.

    Returns
    -------
    string
        The keyword from the input that matches allowable options.
    """
    if type(multiple_choice) is dict:
        multiple_choice = multiple_choice.keys()
    while True:
        if prompt is None:
            response = input('> ')
        else:
            response = input('< ' + prompt + ' >\n').lower()
        keywords = [i for i in response.split() if i in multiple_choice]
        if len(keywords) != 1:
            print('Sorry, that is not an option or it wasn\'t recognized.\n'
                  'Try one of the following:')
            print(multiple_choice)
            continue
        else:
            return keywords[0]