aprenda python en 3 días

test91

name = "mbox-short.txt"                     # the name of the file with the text source
handle = open(name)                         # "store" the file temporally into a handle variable
cou=dict()                                  # defines a dictionary named cou
correos=list()                              # defines a list called correos

#correos create a list with every mail address
for line in handle:                             # check for every line of the file with text
    if not line.startswith("From:") : continue  # if the line don´t start with "From:" pass to the next line
    words=line.split()                          # else store the line in the list named words with every component 
                                                # separated by a space splitted as a different ellement
    correos.append(words[1])                    # words(1) is the second element of the list with the email address

#with correos (list with every email address) will generate a dictionary named cou
for acum in correos:                        # acum counts how many elements will have the dictionary cou 
                                            # accumulate the unique elements
    if acum not in cou:                     # if the email is repeated skip,, don´t increase acum
        cou[acum]=1                         # else increase acum in 1 unit
    else:                                   # otherwise
        cou[acum]=cou[acum]+1               # adds 1 to the value of cou (how many times an email address is repeated)

#then select the most frequent mail and how many times appear
maxval=None                                 # initializate maxval to acumulate the maximun value (times of repitence)
maxname=None                                # ditto for the mail address
for kee,val in cou.items():                 # inspect every pair address-value in the dictionary
    if maxval==None: maxval=val             # in the first inspection maxval equals the first value inspected
    if maxval < val:                        # if the value currently inspected is lower than the current value in cou
        maxval=val                          # replace maxval for current value of cou
        maxname=kee                         # replace name of address with current value in maxname
print maxname, maxval