Created
March 4, 2012 00:44
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Generation of De Bruijn sequence using BitVector
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// generates a binary De Bruijn sequence over words of length n | |
private BitVector generateDeBruijn(int n) { | |
// Check arguments | |
if (n < 0) throw new IllegalArgumentException("n is negative"); | |
if (n > 31) throw new IllegalArgumentException("n exceeds 31"); | |
// There are 2^n words in the entire sequence | |
int length = 1 << n; | |
// Create a set that records which words we have already seen | |
Set<Integer> memory = new BitVector(length).asSet(); | |
// Store the sequence with an extra n bits | |
// makes things easier for enumerating the values | |
BitVector sequence = new BitVector(length + n); | |
// Seed the sequence with the initial value (n 1s) | |
sequence.setRange(0, n, true); | |
// Populate the sequence | |
for (int i = 0; i < length; i++) { | |
// Extract the current word from the sequence | |
int word = (int) sequence.getBits(i, n); | |
// Record that we've seen it | |
memory.add(word); | |
// Shift the word left, populating the rightmost bit with zero | |
// if we've seen the word before, use a one instead | |
sequence.setBit(i + n, memory.contains(word >> 1)); | |
} | |
return sequence; | |
} |
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