Return position of element in Python tuple

index_in_tuple.py

def index_in_tuple(value, iterable):
    return [num for num, val in enumerate(iterable) if val is value][0]

# Works for lists too, but those already have this functionality built in.
# How it works:
# value = "three"
# iterable = ("one", "two", "three", "four")
# enumerate(iterable) => ( (0, "one"), (1, "two") ... )
# num for num, val => 0, "one" [...] # num refers to the '0' in this case
# ..."if val is value" => but only if "one" is "three" (which it's not)
# after evaluating, we'd have something like: return [2][0], which is just "2", as an int.
# the [0] is not necessary if you want a list of all positions of an element within a tuple:
# ("one", "two", "three", "four", "three") would be evaluated to [2,4]
# The current code would return only the 2, but if you wanted all values, you could remove the [0].

# iterable = ("one", "two", "eight", "eleven")
# index = index_in_tuple("eight", iterable)
# segment = iterable[index:] # ("eight", "eleven")