feed-pigeons

gistfile1.py

def checkio(number):
    if number == 1:
        return 1
    elif number < 1000000:
        L = list()
        eat = number
        def  pigeons():
            for p in range(1, number+1):
                L.append(p)
                yield sum(L)
        pgn = pigeons()
        maximum = 0
        while True:
            p = next(pgn)
            for e in range(1,p+1):
                eat = eat - 1
                if maximum < e: maximum = e
                if eat == 0: return maximum

http://www.checkio.org/mission/feed-pigeons/publications/shreekar/python-3/feeding-pegions/