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某問題を解くためのプログラム(R版)
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| ## 某問題をしらみ潰し方式で解くためのプログラム | |
| n <- 200 | |
| doors <- integer(n) # 配列の準備(0でリセットされる) | |
| for (i in 1:100) { | |
| idx <- seq(i, n, i) # 200を超えないiの倍数を指定 | |
| doors[idx] = doors[idx] + 1 # そのドアの開閉の回数を+1(奇数なら開、偶数なら閉) | |
| } | |
| Open <- (doors %% 2 == 1) # 奇数であれば(ドアが開いている)TRUE、偶数ならFALSE | |
| ## (1) | |
| print(which(Open[1:10])) # 開いているロッカーのインデックス | |
| ## (2) | |
| print(doors[99:101]) # 開閉の合計数 | |
| ## (3) | |
| print(sum(Open)) # 開いているロッカーの合計数(TRUEの個数) |
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