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January 19, 2021 02:20
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A tiny introduction to recursion in Python
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from typing import List, Optional, Sequence | |
# A recursive function is a function that calls itself. They're an alternative option to iteration, like using a while | |
# or for loop. Sometimes, they can make code easier to read and write. The examples below are overly simplified and | |
# have obviously better alternatives. | |
def multiply_string(s: str, n: int) -> str: | |
# There are 3 main parts to a recursive function. | |
# 1. A way to go to either the base case (no recursion) or recursive case (function calls itself). | |
if n == 0: # The switch between base and recursive is often an if statement. | |
# 2. The base case. This is the case that doesn't require recursion. | |
return '' # Any string times 0 is empty string. That's easy. | |
# 3. The recursive case. This same function gets called again, but slightly differently. | |
# This needs to eventually get to the base case. | |
return s + multiply_string(s, n - 1) # Add the string to result of multiplying the string times n -1. | |
# Eventually, n will be 0 and we'll be at the base case. | |
# This is also a good order to first write your recursive functions, even if you rewrite in a different order later. | |
# 1. What input is the base case? | |
# 2. What calculation needs to be done for the base case (if any)? | |
# 3. What calculation needs to be done for the recursive case? | |
# For the base case, there are some common patterns. It's often when an integer input is 0 or 1, the collection is | |
# totally empty, or you're at the thing you're looking for. A good question is: "What's the easiest possible case?" | |
# There can also be more than one base case! You've searched everywhere and haven't found the thing could be one | |
# base case, and you've found the thing could be another. | |
# For the recursive case, it's often easiest to think of being one step away from a base case. If your base case is | |
# n=0, think of how to get from n=0 to n=1. This is usually easier than how to get from n=9 to n=10. | |
def triangle_number(n: int) -> int: | |
"""Calculate the sum of 1, 2, n. This is like a triangle with n items on the bottom.""" | |
if n == 0: # Easy case. n == 1 is just as easy, but this way our function also supports 0. | |
return 0 | |
return n + triangle_number(n - 1) # This will sum the numbers from highest to lowest. The calculation is like: | |
# (3 + (2 + (1 + (0)))) | |
# Recursive functions often have default arguments. These aren't used when you call the function from the outside, | |
# but they are used when you call the function recursively. They often hold data about the path to get where you are, | |
# or what you've already looked at. | |
def contains(item: object, sequence: Sequence, index: int = 0) -> bool: | |
# When this function gets called by a user, they won't provide an index and we'll start at 0. | |
if index == len(sequence): # This means we've gone past the last index in the sequence. | |
return False | |
if sequence[index] == item: # Another base case. We've found the item. | |
return True | |
# For the recursion, the item stays the same, the sequence stays the same, but let's check what's at the next index. | |
# Any outside user of this function won't provide the index, but we can provide it now and check the next item. | |
return contains(item, sequence, index + 1) | |
# The default arguments also might be mutated. This can help runtime. Rather than create a new thing every time, | |
# just mutate what was provided. Maybe you return it at the end. | |
def path_to_zero(n: int, path: Optional[List[int]] = None) -> List[int]: | |
"""Returns a list of how to get from n to 0 by subtracting 1.""" | |
if path is None: # Classic Python mutable default stuff. | |
path = [] | |
if n == 0: # If we're already at 0 (the end) | |
path.append(0) # Our base case, no recursion required. | |
return path | |
else: | |
path.append(n) # Put the current number on the path. | |
path_to_zero(n - 1, path) # The path will get mutated in the recursive calls, adding the remaining numbers. | |
return path | |
# It can be helpful to write recursive functions in a verbose (if: base case, else: recursive) way, then refactor | |
# them to be simpler. Here's the function above, refactored. | |
def path_to_zero_refactored(n: int, path: Optional[List[int]] = None) -> List[int]: | |
if path is None: | |
path = [] | |
path.append(n) # Add the number we're at. | |
if n: # If we're not at 0 | |
path_to_zero_refactored(n - 1, path) # Add the next thing until we are. | |
return path | |
# A good exercise is translating recursive functions to iterative, or vice versa. | |
def path_to_zero_iterative(n: int) -> List[int]: | |
# This isn't the best code, but it's the closest to the recursive version above. | |
path = [] | |
while n != 0: # Recursive to iterative translations will often have "while not base case" loops. | |
path.append(n) | |
n -= 1 # This is the same transformation to n that happens in the recursive call above. | |
path.append(0) # Our while loop skips the base case, so we do it here. | |
return path | |
# The above examples are contrived, but this is an example where the recursive version makes for code that's just | |
# as good or better than the iterative version. | |
def collatz(n: int, steps: int = 0) -> int: | |
"""Calculates how many steps to get from n to 1 following the Collatz rules. | |
The Collatz rules are: | |
If the number is even, get the next number by dividing it by 2. | |
If the number is odd, get the next number by multiplying by 3 and adding 1. | |
""" | |
if n == 1: # We're at the end. | |
return steps | |
elif n % 2 == 0: # If n is even | |
return collatz(n // 2, steps + 1) | |
else: # n is odd | |
return collatz(n * 3 + 1, steps + 1) # Woah, a second recursive case! | |
# A downside to recursion in Python is that there is a limit to the call stack. This means there's a limit to how | |
# deep your recursion can go. The default is 1,000. | |
def deep_recursion(): | |
"""Requires over 1,000 recursive calls, raising a RecursionError on most Python implementations.""" | |
collatz(9780657630) | |
# Those are some recursion in Python basics. Go find some other recursive problems and enjoy! |
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