Created
December 12, 2023 08:34
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Advent Of Code - Day 1
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#include <iostream> | |
#include <fstream> | |
#include <string> | |
#include <ctype.h> | |
#include <math.h> | |
using namespace std; | |
int main() | |
{ | |
ifstream infile("input.txt"); | |
if (!infile.is_open()) { | |
cout << "File prob\n"; return -1; | |
} | |
string line; | |
unsigned long long sum = 0; | |
string nums[10]{ "zero", "one", "two", "three", "four", "five", "six", "seven", "eight", "nine" }; | |
while (infile.good()) { | |
getline(infile, line); | |
int idxs[10]{ -1,-1,-1,-1,-1,-1,-1,-1 }; | |
int maxidxs[10] = { -1,-1,-1,-1,-1,-1,-1,-1 }; | |
long long minIdx = 99999999, firstN = 0, lastN = 0, maxIdx = -1; | |
// Find the index of first and last digit or 'digit word' | |
for (size_t i = 0; i < 10; i++) { | |
idxs[i] = min(line.find(nums[i], 0), line.find(to_string(i), 0)); | |
maxidxs[i] = max(static_cast<int>(line.rfind(nums[i])), static_cast<int>(line.rfind(to_string(i)))); | |
} | |
// Look through the indexes and get the actual first and last digit | |
for (size_t i = 0; i < 10; i++) { | |
if (idxs[i] != -1 && idxs[i] < minIdx) { | |
minIdx = idxs[i]; | |
firstN = i; | |
} | |
if (maxidxs[i] > maxIdx) { | |
maxIdx = maxidxs[i]; | |
lastN = i; | |
} | |
} | |
sum += (10 * firstN) + lastN; | |
} | |
cout << "Sum " << sum << "\n"; | |
infile.close(); | |
} |
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